//week4.cpp //instructions: copy line long msg into a file named data.txt (single line, no spaces) //compile with the following //g++ -o week4 week4.cpp //run atcommand line: week4 < data.txt > outfile.txt #include <stdio.h> int main(int argc, char * argv[]) { unsigned char byte = 0; int bits = 0; for(;;) { char buffer[1024]; int len = fread(buffer, 1, sizeof(buffer), stdin); // if there was a read error or EOF, stop if (len <= 0) break; for(int i = 0; i < len; ++i) { switch(buffer[i]) { // if a binary 1, turn on bit zero case '1': byte |= 1; break; // if a binary 0, do nothing case '0': break; // if antyhing else, skip default: continue; } // incrment the counter, if we dont yet have 8 bits // shift all the bits left by one if (++bits < 8) byte <<= 1; else { // write out the complete byte fwrite(&byte, 1, 1, stdout); // reset for the next byte bits = 0; byte = 0; } } } // write out any remaining data if the input was not a multiple of 8 in length. if (bits) fwrite(&byte, 1, 1, stdout); return 0; }

binary = "00100010010010000110010101101100011011000110111100100000011001100111001001101111011011010010000001110100011010000110010100100000011000110110100001101001011011000110010001110010011001010110111000100000011011110110011000100000011100000110110001100001011011100110010101110100001000000100010101100001011100100111010001101000001011100010001000100000001011010010000001010110011011110111100101100001011001110110010101110010001000000011000100100000001001100010000000110010001011000010000000110001001110010011011100110111" ans = "" for i in range(0, len(binary), 8): heheha = binary[i:i+8] ans += chr(int(heheha, 2)) print(ans)

def binary_to_text(binary: str) -> str: input_bytes: list[str] = [binary[bit:bit + 8] for bit in range(0, len(binary), 8)] char_values: list[str] = [] for byte in input_bytes: char_values.append(chr(int(byte, 2))) return "".join(char_values)

fn main() { const BITS: &str = "00100010010010000110010101101100011011000110111100100000011001100111001001101111011011010010000001110100011010000110010100100000011000110110100001101001011011000110010001110010011001010110111000100000011011110110011000100000011100000110110001100001011011100110010101110100001000000100010101100001011100100111010001101000001011100010001000100000001011010010000001010110011011110111100101100001011001110110010101110010001000000011000100100000001001100010000000110010001011000010000000110001001110010011011100110111"; let mut out = String::new(); for i in (0..BITS.len()).step_by(8) { let byte = u8::from_str_radix(&BITS[i..i + 8], 2).unwrap(); out.push(byte as char); } println!("{}", out); }

FUNCTION BINARYTOTEXT(binary:STRING) RETURNS STRING DECLARE Result:INTEGER DECLARE ReturnString:STRING ReturnString ← "" FOR Count ← 1 TO LENGTH(binary) STEP 8 Result ← 0 FOR I ← 7 TO 0 STEP -1 IF MID(binary,(Count+7-I),1) = "1" THEN Result ← Result + (2^I) ENDIF NEXT I ReturnString ← ReturnString & CHR(Result) NEXT Count RETURN ReturnString ENDFUNCTION

//Paste your solution here if you want to share it publicly message = input() n = len(message) // 8 for i in range(n): a = message[i * 8 : (i + 1) * 8] b = int(a, 2) print(chr(b), end="")

// https://program52.com/en/challenge/2026/5B7BB05B5 // - use "odin run ." to run the code // - input1.txt and input2.txt should be nearby with the input data package main import "core:fmt" import "core:strconv" import "core:strings" input1_bytes := #load("input1.txt") input2_bytes := #load("input2.txt") main :: proc () { for bytes in ([2] [] byte { input1_bytes, input2_bytes }) { text := strings.trim(string(bytes), "\n\r\t ") for line in strings.split_lines(text) { result := decode(line) fmt.printfln("->|%s|\n<-|%s|", line, result) } } } decode :: proc (input: string, allocator := context.allocator) -> string { assert(len(input)%8 == 0, "input length must be divisible by 8") sb := strings.builder_make(allocator) for i in 0..<len(input)/8 { text := input[i*8:(i+1)*8] number, ok := strconv.parse_int(text, base=2) assert(ok) strings.write_rune(&sb, rune(number)) } return strings.to_string(sb) }

binary_string = "00100010010010000110010101101100011011000110111100100000011001100111001001101111011011010010000001110100011010000110010100100000011000110110100001101001011011000110010001110010011001010110111000100000011011110110011000100000011100000110110001100001011011100110010101110100001000000100010101100001011100100111010001101000001011100010001000100000001011010010000001010110011011110111100101100001011001110110010101110010001000000011000100100000001001100010000000110010001011000010000000110001001110010011011100110111" # Split the binary string into 8-bit chunks binary_chunks = [binary_string[i:i+8] for i in range(0, len(binary_string), 8)] # Convert each binary chunk to its corresponding character decoded_text = ''.join([chr(int(chunk, 2)) for chunk in binary_chunks]) print("Decoded text:") print(decoded_text) print("\n--- Alternative formatting ---") # Let's also show the process step by step print("\nCharacter-by-character breakdown:") for i, chunk in enumerate(binary_chunks): char = chr(int(chunk, 2)) print(repr(char))

#include <stdio.h> #include <string.h> #include <stdlib.h> int main() { char inString[1024]; scanf("%s", inString); int len = strlen(inString); int numNibbles = len / 4; // Arrays to store the intermediate steps char hexStore[numNibbles + 1]; // 1 & 2: Process binary into Hex characters for (int i = 0; i < numNibbles; i++) { // Look at a 4-bit chunk char chunk[5]; strncpy(chunk, &inString[i * 4], 4); chunk[4] = '\0'; // Convert the 4-bit string to a hex char if (strcmp(chunk, "0000") == 0) hexStore[i] = '0'; else if (strcmp(chunk, "0001") == 0) hexStore[i] = '1'; else if (strcmp(chunk, "0010") == 0) hexStore[i] = '2'; else if (strcmp(chunk, "0011") == 0) hexStore[i] = '3'; else if (strcmp(chunk, "0100") == 0) hexStore[i] = '4'; else if (strcmp(chunk, "0101") == 0) hexStore[i] = '5'; else if (strcmp(chunk, "0110") == 0) hexStore[i] = '6'; else if (strcmp(chunk, "0111") == 0) hexStore[i] = '7'; else if (strcmp(chunk, "1000") == 0) hexStore[i] = '8'; else if (strcmp(chunk, "1001") == 0) hexStore[i] = '9'; else if (strcmp(chunk, "1010") == 0) hexStore[i] = 'A'; else if (strcmp(chunk, "1011") == 0) hexStore[i] = 'B'; else if (strcmp(chunk, "1100") == 0) hexStore[i] = 'C'; else if (strcmp(chunk, "1101") == 0) hexStore[i] = 'D'; else if (strcmp(chunk, "1110") == 0) hexStore[i] = 'E'; else if (strcmp(chunk, "1111") == 0) hexStore[i] = 'F'; } hexStore[numNibbles] = '\0'; // 3: Convert Hex pairs to ASCII characters for (int i = 0; i < numNibbles; i += 2) { // Take two hex digits (8 bits total) and convert to a byte char hexPair[3] = { hexStore[i], hexStore[i+1], '\0' }; // strtol converts the string base-16 to a long integer int asciiVal = (int)strtol(hexPair, NULL, 16); printf("%c", (char)asciiVal); } printf("\n"); return 0; }

Encoded = "00100010010010000110010101101100011011000110111100100000011001100111001001101111011011010010000001110100011010000110010100100000011000110110100001101001011011000110010001110010011001010110111000100000011011110110011000100000011100000110110001100001011011100110010101110100001000000100010101100001011100100111010001101000001011100010001000100000001011010010000001010110011011110111100101100001011001110110010101110010001000000011000100100000001001100010000000110010001011000010000000110001001110010011011100110111" Decoded = int(Encoded, 2).to_bytes(len(Encoded) // 8, 'big').decode() print(Decoded)

DECLARE binaryStr, message : STRING DECLARE index : INTEGER binaryStr ← "00100010010010000110010101101100011011000110111100100000011001100111001001101111011011010010000001110100011010000110010100100000011000110110100001101001011011000110010001110010011001010110111000100000011011110110011000100000011100000110110001100001011011100110010101110100001000000100010101100001011100100111010001101000001011100010001000100000001011010010000001010110011011110111100101100001011001110110010101110010001000000011000100100000001001100010000000110010001011000010000000110001001110010011011100110111" FOR index ← 1 TO LENGTH(binaryStr) STEP 8 message ← message & byteToChar(MID(binaryStr, index, 8)) NEXT index OUTPUT message FUNCTION byteToChar(byte : STRING) RETURNS CHAR DECLARE posVal, sum, stringIndex : INTEGER posVal ← 128 sum ← 0 stringIndex ← 1 WHILE posVal >= 1 DO IF MID(byte, stringIndex, 1) = "1" THEN sum ← sum + posVal ENDIF posVal ← posVal DIV 2 stringIndex ← stringIndex + 1 ENDWHILE RETURN CHR(sum) ENDFUNCTION